Question

find the area of equlatral triangle haveing each side of length 10 cm

Answer 1

Correct Question :-

Find the area of the equilateral triangle having each side of length 10cm.

AnswEr :-

Area is$\sf\; \bold\; 25\sqrt{3}\;cm^2.$

Step by step Explanation:-

Given :-

length of Side = 10cm

And,

$\sf \implies\ Side \; = \;\Large \frac{a\;+\;b\;+\;c}{2}$

Now,

$\sf\implies \; Side \; = \; \Large\frac{10\;+\;10\;+\;10}{2}$

$\sf \implies \; Side = \Large\frac{30}{2}$

$\sf\implies\;Side\; =\; 15\;cm$

Finding Area of Triangle :-

$\sf\sqrt{15(15 - 10)(15 - 10)(15 - 10)}$

$\sf\implies\; \sqrt{15 \; \times\; 5\times\;5\times\;5}$

$\sf\implies\;25\sqrt{3}\;cm^2$

So, The area of equilateral triangle is$\sf\; </strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>l</strong><strong>d</strong><strong>\</strong><strong>;</strong><strong> </strong><strong>25\sqrt{3}\;cm^2$.

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