Find the area of figure formed by a square of side 8cm and an isosceles triangle with bases one side of the square and perimeter as 18.
Answers
Answered by
25
the isosceles triangle has perimeter = 18
base = 8 cm
so the equal sides = (18 - 8) /2 = 5
altitude and area are shown in the diagram... total area = 76
area of the isosceles triangle can be also found using the formula of Heron:
Δ = √[s (s-a) (s-b)(s-c)
here a = 8, b = 5 c = 5 so s = (8+5+5)/2 = 9
Δ = area = √[ 9*1*4*4] = 12 sq cm
Add this to the area of square = 8 * 8 = 64 cm²
total 76 cm²
base = 8 cm
so the equal sides = (18 - 8) /2 = 5
altitude and area are shown in the diagram... total area = 76
area of the isosceles triangle can be also found using the formula of Heron:
Δ = √[s (s-a) (s-b)(s-c)
here a = 8, b = 5 c = 5 so s = (8+5+5)/2 = 9
Δ = area = √[ 9*1*4*4] = 12 sq cm
Add this to the area of square = 8 * 8 = 64 cm²
total 76 cm²
Attachments:
priyankasharma:
i am your big fan sir thanks a lot
Answered by
19
area of the square= 8x8 = 64sq.cm
area of triangle= (1/2) base x height
base=8cm.
Since the triangle is isosceles, the other 2 sides would be equal measuring 5cm each.
Height could be found using Pythogoras theorem[5^2- 4^2=3^2], we get height=3cm.
Area of triangle=(1/2)(3)(8)=12sq.cm
64+12=76 sq.cm
area of triangle= (1/2) base x height
base=8cm.
Since the triangle is isosceles, the other 2 sides would be equal measuring 5cm each.
Height could be found using Pythogoras theorem[5^2- 4^2=3^2], we get height=3cm.
Area of triangle=(1/2)(3)(8)=12sq.cm
64+12=76 sq.cm
Similar questions