Question

find the area of figure p q r s t u please solve kar do na bilkul samajh nahin a Raha​

Answer 1

Answer:

3550

Step-by-step explanation:

Let the points between the markings '15' and '60' be V, '40' and '25' be W and '30' and '10' be Y.

Now let's find the area of the ∆PQW

We can chalk out that it is a right-angled triangle and thus its area would be

$a = \frac{1}{2} \times (100 - 60) \times 25 \\ a = \frac{1}{2} \times 40 \times 25\\ a = 20 \times 25 \\ a = 500$

Now for the area of the ∆RQW

Similarly, this is also a right-angled triangle and its area would be

$b = \frac{1}{2} \times 60 \times 25 \\ b = 30 \times 25 \\ b = 750$

For ∆UPY

$c = \frac{1}{2} \times 30 \times 10 \\ c = 150$

Now for the trapezium TWYU

$d= \frac{1}{2} \times (15 + 30) \times 40 \\ d = 45 \times 20 \\ d = 900$

Now for the trapezium TVRS

$e= \frac{1}{2} \times (100 - (40 + 10)) \times (35 + 15) \\ e = \frac{1}{2} \times 50 \times 50 \\ e = 50 \times 25 \\ e= 1250$

Now adding all the areas together

$a + b + c + d + e = 500 + 750 + 150 + 900 + 1250 \\ total \: area = 3550$