Question

Find the area of four walls of a room of 7.5 m long, 4.5 m broad and 3m high. Also, find the cost of plastering its floor, ceiling and four walls at the rate of ₹ 12 per square metre, neglecting the areas of door and window.



Please solve this problem step by step....... ​

Answer 1

Answer:

The area of walls including the floor and ceiling is 72 $m^{2}$.. The cost of plastering is ₹1674...

Step-by-step explanation:

L.S.A of room = 2h (l+b)

                             = 2 x 3 ( 7.5 + 4.5 )

                            = 6 x 12

                            = 72 $m^{2}$

Cost of Plastering = ₹ 12 x T.S.A

                              = ₹ 12 x 139.5

                              = ₹1674

Answer 2

Step-by-step explanation:

Area of four walls of the room (L.S.A) = 2(l+b)×h

= 2(7.5+4.5) × 3

= (2×12×3) m2

= 72 m2

Now, T.S.A of the room = 2(lb+bh+lh)

= 2( 7.5× 4.5 + 4.5×3 + 7.5×3) m2

= 2( 33.75 + 13.5 + 22.5) m2

= (2 × 69.75) m2

= 139.5 m2

Cost of plastering = Rs.(139.5× 12)

= Rs.1,674

Sorry but the answer maybe wrong because you have not given the dimensions of door and window.