find the area of given figure
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in ∆ABC, AC²=AB²+BC² ( By Pythagoras theorem)
AC²= 81+144=225
AC=√225=15
In∆ACD, AD²=AC²+CD²
17²=15²+CD²
289-225= CD²
√64=CD
CD=8
WE KNOW THAT AREA OF TRIANGLE IS EQUAL TO 1/2XBASEX HEIGHT
AREA OF THE GIVEN FIGURE= AREA OF ABC+AREA OF ACD
=1/2X12X9+1/2X8X15
=54+60=114
THEREFORE AREA =114(unit) ²
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