Question

find the area of given figures​

Answer 1

Answer:

$52 \: {cm}^{2}$

Step-by-step explanation:

Length of the larger rectangle: (4 + 2 + 3 + 2) cm

→11 cm.

Breadth of the larger rectangle: 4cm.

Area of the Larger rectangle: (l × b) unit.

→11 × 4

$=> {44 \: cm}^{2}$

Side of each Square: 2 cm.

Area of the each Square:

${s}^{2}$

$= > {2}^{2}$

$= > 4 \: {cm}^{2}$

Number of squares: 2.

Area of both square: 4 sq. cm.

Total Area of both Squares: 2 × 4 sq. cm.

$= > 2 \times 4 \: {cm}^{2}$

$= > 8 \: {cm}^{2}$

Total Area of the figure: 44 + 8 sq. cm.

$= > 44 + 8$

$= > 52 \: {cm}^{2}$

Hence, area of the figure is 52 sq. cm.

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