find the area of given polygon
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Answer:
ar ( ABCD ) = 390 cm²
Step-by-step explanation:
Join BD .
Now , in ∆ABD , Angle A = 90°
Hence , area of ∆ABD = ( 1 / 2 ) * Base * Height
= ( 1 / 2 ) * 40 * 9
= 180 cm²
Now , in ∆CDB , Angle C = 90°
Hence ,
Area of ∆CDB = ( 1 / 2 ) * Base * Height
= ( 1 / 2 ) * 28 * 15
= 210 cm²
Now , area of polygon ABCD = Area of ∆ABD + Area of ∆CDB = ( 180 + 210 ) cm² = 390 cm² .
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