Question

find the area of isosceles right angle triangle whose equal side is 12 cm long 12 cm hight ​

Answer 1

Step-by-step explanation:

$\qquad\qquad\sf {:}\longrightarrow 1/2×12×12$

$\qquad\qquad\sf {:}\longrightarrow 1/2×12^2$

$\qquad\qquad\sf {:}\longrightarrow 1/2×144$

$\qquad\qquad\sf {:}\longrightarrow 144/2$

$\qquad\qquad\sf {:}\longrightarrow 72$

Answer 2

REQUIRED ANSWER:

Area of triangle is 72cm².

EXPLANATION:

Here in this question we have given an isoscele triangle with given length of equal sides and we have to find area of that triangle.

So let's start!

★ Area of right ∆ =½×base×height

=> (½×12×12)cm²

=> (6×12)cm²

=> 72cm²

Hence the required area of triangle is 72cm².

RELATED INFORMATION:

⊙ What is an isosceles triangle?

~Isosceles triangle is one in which 2 sides are equal in length.

⊙ What is an equilateral triangle?

~Equilateral triangle is one in which each side is equal in length and angles formed by vertices of triangle is also equal to 60° each.

⊙ What is a right angled triangle?

~Right angled triangle is one in which one angle is of 90° and other 2 are acute angles.