Question

find the area of isosceles triangle in which parameter is 42 cm and each equal side is 15 cm​

Answer 1

Answer:

$18 \sqrt{21} {cm}^{2}$

Step-by-step explanation:

see in above fig:

Answer 2

Step-by-step explanation:

third side of triangle = 42-(15+15)

= 12cm

altitude = root(15²-6²)

=

root(225-36)

= root(189)

= 13.7477