Question

Find the area of isosceles triangle whose equal side is 6cm,6cm and 8cm

Answer 1

AnswEr-:

$\frak{\bf{\pink {Given \:\: -:}}} \begin{cases} \sf{The\: \:\:first\:side\:of\:the\:isosceles \:triangle \: \:is\:= \frak{6\:cm}} & \\\\ \sf{The\: \:\:Second \:side\:of\:the\:isosceles \:triangle \: \:is\:= \:=\:\frak{6\:cm}}& \\\\ \sf{The\: \:\:Third \:side\:of\:the\:isosceles \:triangle \: \:is\:= \:=\:\frak{8\:cm}}\end{cases}$

$\frak{\bf{\pink{To\:Find \:-: }}}\:\:\sf{ The\:Area\:of\:Isosceles \:Triangle \:.}$

$\mathrm {\bf{ Solution \:of\:Question \:-:}}$

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$\qquad \quad \sf{\bf{ Finding\:Semi-Perimeter\:(S) \:-:}}$

• $\boxed {\mathrm {\pink{ Semiperimeter(S) = \dfrac{ First \:Side(A) + Second \:Side\:(B) + Third\:SideC) }{2}}}}$

$\qquad \quad \sf{\underline {\star{ Now \:By\:Putting \:the \:Given \:Values\:-:}}}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Semi-Perimeter\:(S) = \dfrac{6 + 6 + 8 }{2} }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Semi-Perimeter\:(S) = \dfrac{12+ 8 }{2} }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Semi-Perimeter\:(S) = \dfrac{20 }{2} }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Semi-Perimeter\:(S) = \dfrac{\cancel {20} }{\cancel {2}} }}$

$\qquad \quad \qquad \quad \underline {\boxed{\pink{\mathrm { Semi-Perimeter \: (S) \: = 10cm }}}}$

Therefore,

$\dag\:\: {\underline{\pink{\mathrm { Semi-Perimeter \: (S) \:of\:Isosceles \;Triangle = 10cm }}}}$

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$\qquad \quad \sf{\bf{ Finding\:Area \:-:}}$

• $\boxed {\mathrm {\pink{ Area = \sqrt{ s(s-a)(s-b)(s-c)} }}}$

$\frak{\bf{\pink {Here \:\: -:}}} \begin{cases} \sf{The\: \:\:first\:side\:of\:the\:isosceles \:triangle \: \:is\:(a)\:= \frak{6\:cm}} & \\\\ \sf{The\: \:\:Second \:side\:of\:the\:isosceles \:triangle \: \:is\:(b)\:= \:=\:\frak{6\:cm}}& \\\\ \sf{The\: \:\:Third \:side\:of\:the\:isosceles \:triangle \: \:is\:(c)= \:=\:\frak{8\:cm}}& \\\\ \sf{The\: \:\:Semi-Perimeter\:of\:the\:isosceles \:triangle \: \:is\:(s)= \:=\:\frak{10\:cm}}\end{cases}$

$\qquad \quad \sf{\underline {\star{ Now \:By\:Putting \:the \:Given \:Values\:-:}}}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Area = \sqrt{10 (10-6)(10-6)(10-8) } }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Area = \sqrt{10 \times 4 \times 4 \times 2 } }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Area = \sqrt{5 \times 2\times 2 \times 2 \times 2\times 2 \times 2 } }}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Area = \sqrt{5 \times 2^{2} \times 2^{2} \times 2^{2} } }}$

$\sf{\bf{ \sqrt{a \times y^{2}} = \sqrt[y]{a}}}$

$\qquad \quad \qquad \quad \longmapsto {\mathrm { Area =2 \times 2 \times 2 \sqrt{5 } }}$

$\qquad \quad \qquad \quad \underline {\boxed{\pink{\mathrm { Area \: = 8\sqrt{5} cm^{2} }}}}$

Hence ,

$\dag\:\: {\underline{\pink{\mathrm { Area\:of\:Isosceles \;Triangle = 8\sqrt{5} cm^{2} }}}}$

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Answer 2

Answer:

QUESTION

Find the area of isosceles triangle whose equal side is 6cm,6cm and 8cm.

ANSWER

$\fbox \red{area \: of \: triangle} = \frac{1}{2} \: \: ( 8cm \times 6cm) \\ \\ \blue {\frac{1}{2} \: \div 48 = 24cm} \\ \\ \fbox \green{FORMULA USED} \\ \\ \frac{1}{2}(b \times h)$

I hope it helps you

#SILENT GIRL ANSWER