Question

find the area of isosceles triangle whose perimeter is 32 cm and the ratio of the equal side to its base is 3:2 .

Answer 1

The perimeter of isosceles triangle = 32cm

p of isosceles triangle = 2 * equal side + base

let length of equal side be 3x and base be 2x

then

m2 * 3x + 2x = 32 cm

6x + 2x = 32cm

8x = 32 cm

x= 4 cm

length of equal side = 3*4= 12cm

length of base = 2*4=8cm

area of isosceles triangle=b*1/4*√4a2-b2

= 8*1/4√4*144-64

=2√512

=2*22.62

= 45.25cm2_______answer


hope it will help you..