Question

Find the area of parallelogram A B C D

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Answer 1

Answer:

Step-by-step explanation:

we an divide parallelogram into 2  triangles.

area of 1st triangle = 1/2 x base x height

= 1/2 x 10 x 13

= 5 x 13

=65 cm sq.

65  x 2 = 130

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Answer 2

Symbols Meaning:-

∠ = Angle

△ = Triangle

∴ = Hence

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The parallelogram ABCD can be written as Triangle ABC + Triangle ADC

=> AC = AC = 10 cm( because they are same sides)

=> AD = BC = 13cm (because in a parallelogram opposite sides are equal)

=> ∠BAC and ∠ACD = 70°(because in parallel lines corresponding angles are equal)

=> Area of parallelogram = Area of △ABC + △ADC

=> Area of triangle

= 1

--- x base x height

2

= 1

--- x 10 x 13

2

= 1× 5 x 13 (when simplified)

= 65cm²

(Both the triangles measure the same because they are the halves of the parallelogram and AC is the bisector of the parallelogram ABCD)

So △ABC + △ADC = 65cm² + 65cm² = 130cm².

∴ Area of Parallelogram = 130cm²