Math, asked by SMHANUSH, 1 month ago

find the area of parallelogram shaped shaded region .Also find the area of each triangle .What is the ratio of the area of shaded portion to the remaining area of the triangle ?​

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Answers

Answered by Srinjay23
176

Answer:

In DEBF the base is FB and height is AD.

We know area of a parallelogram is base x height

Area of DEBF = FB x AD

= (10-4)cm × 6 cm

= 6 cm × 6 cm

= 36 cm2

In DAF the base is AF and height is AD

area of a triangle is 1/2 x base x height

= 1/2 × 4 × 6 cm

= 12 cm2

In BCE the base is EC and height is CB

area of a triangle is 1/2 x base x height

= 1/2 x 4 x 6 cm2

= 12 cm2

Area of each triangle is 12 cm.

Area of unshaded part = 12 cm2 + 12 cm2

= 24 cm2

Ratio of shaded part to left over area in rectangle is 36 : 24

= 3 : 2

HOPE IT HELPS PLZ MARK AS BRAINLIEST

Answered by mayankhandique874
7

Answer:

3:2 I don't know just don't see

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