find the area of parallelogram shaped shaded region .Also find the area of each triangle .What is the ratio of the area of shaded portion to the remaining area of the triangle ?
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Answered by
176
Answer:
In DEBF the base is FB and height is AD.
We know area of a parallelogram is base x height
Area of DEBF = FB x AD
= (10-4)cm × 6 cm
= 6 cm × 6 cm
= 36 cm2
In DAF the base is AF and height is AD
area of a triangle is 1/2 x base x height
= 1/2 × 4 × 6 cm
= 12 cm2
In BCE the base is EC and height is CB
area of a triangle is 1/2 x base x height
= 1/2 x 4 x 6 cm2
= 12 cm2
Area of each triangle is 12 cm.
Area of unshaded part = 12 cm2 + 12 cm2
= 24 cm2
Ratio of shaded part to left over area in rectangle is 36 : 24
= 3 : 2
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Answered by
7
Answer:
3:2 I don't know just don't see
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