Find the area of parallelogram whose diagonals are 2i and 3j
Answers
Answered by
5
area= 1/2×{2i+3j}
=1/2×2i+3j
=1/2×2i+3j
Answered by
17
Hey dear,
◆ Answer -
3 sq.units
◆ Explanation-
Let vect.a and vect.b be two diagonals of parallelogram.
vect.a = 2i
vect.b = 3j
Area of the parallelogram is calculated by -
A = 1/2 |vect.a × vect.b|
A = 1/2 |2i × 3j|
A = 1/2 |6k|
A = 1/2 × 6
A = 3 sq.units
Area of the parallelogram is 3 sq.units.
Hope it helpz you...
◆ Answer -
3 sq.units
◆ Explanation-
Let vect.a and vect.b be two diagonals of parallelogram.
vect.a = 2i
vect.b = 3j
Area of the parallelogram is calculated by -
A = 1/2 |vect.a × vect.b|
A = 1/2 |2i × 3j|
A = 1/2 |6k|
A = 1/2 × 6
A = 3 sq.units
Area of the parallelogram is 3 sq.units.
Hope it helpz you...
Similar questions