Question

Find the area of pellegram whose base is68 cmand height is 3.8 CM

Answer 1

Step-by-step explanation:

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Answer 2

$\large{\mathrm{Question-: }}$

• Find the area of Parallelogram whose base is 68 cm and height is 3.8 cm.

$\large{\mathrm{AnswEr-: }}$

• $\boxed {\mathrm{Area_{Parallelogram}-: 258.4 cm^{2}}}$

Explanation-:

• $\sf{Given \:-:}$

• The base of Parallelogram is 68 cm

• The Height of Parallelogram is 3.8 cm .

• $\sf{To \:Find-:}$

• The Area of Parallelogram.

$\dag{\sf{Solution \:of\:Question \:-:}}$

• $\underbrace {\sf{Understanding \:the\:Concept \:-:}}$

• We have to find the Area of Parallelogram whose base and height is given .

• For this we have to put the known or Given values in Formula for Area of Parallelogram,

• From this we can get the area of Parallelogram.

As , We know that ,

• $\boxed{\dag{\mathrm {\blue {Area \;of\:Parallelogram \:-: Base \times Height \:sq.units}}}}$

Here-:

• The base of Parallelogram is 68 cm
• The Height of Parallelogram is 3.8 cm .

Now By Putting known or Given Values-:

• $\longrightarrow {\mathrm{Area_{Parallelogram}-: 68 \times 3.8 }}$

• $\longrightarrow {\mathrm{Area_{Parallelogram}-: 258.4 cm^{2}}}$

Hence ,

• $\boxed {\mathrm{Area_{Parallelogram}-: 258.4 cm^{2}}}$

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♡ More To know-:

• Formula of Area -:

• $\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

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