Find the area of pentagon ABCDE in which BL ⊥ AC, CM ⊥ AD and EN ⊥ AD such that AC=10cm, AND=12cm, BL=3cm, CM=7 cm and EN=5cm.
Answers
Answered by
15
Area of pentagon ABCDE = 87 cm²
Step-by-step explanation:
Area of pentagon ABCDE = Area of Δ ABC + Area of ΔACD + Area of Δ ADE
Area of ΔABC = (1/2) * AC * BL ( as BL ⊥AC)
= (1/2)(10)*3
= 15 cm²
Area of ΔACD = (1/2) * AD * CM ( as CM ⊥AD)
= (1/2)(12)*7
= 42 cm²
Area of ΔADE = (1/2) * AD * EN ( as EN ⊥AD)
= (1/2)(12)*5
= 30 cm²
Area of pentagon ABCDE = 15 + 42 + 30 = 87 cm²
Learn more:
find the area of the combined figure given formed by joining a semi ...
https://brainly.in/question/11162606
if pqrst is a regular pentagon and STM is an isosceles triangle with ...
https://brainly.in/question/12926930
Similar questions