Question

Find the area of pentagon with vertices (4, 3),(-5, 6), (-7,-2), (0,-7) and (3, -6)​

Answer 1

Answer:

97²

Step-by-step explanation:

Given vertices are

(

4

,

3

)

,

(

−

5

,

6

)

,

(

−

7

,

−

2

)

,

(

0

,

−

7

)

and

(

3

,

−

6

)

, so the area is,

Δ

=

1

2

∣

∣

∣

x

1

x

2

x

3

x

4

x

5

x

1

y

1

y

2

y

3

y

4

y

5

y

1

∣

∣

∣

=

1

2

∣

∣

∣

4

−

5

−

7

0

3

4

3

6

−

2

−

7

−

6

3

∣

∣

∣

=

1

2

|

39

+

52

+

49

+

21

+

33

|

=

97

sq. units