Question

a rectangular floor measures 3m by 3.4m. Tiles of dimensions 10cm × 12cm are to be laid on it. How many tiles will be required?

please explain in that way that I can understand ​

Answer 1

Answer:

$\sf\huge\green{\underbrace{\red{Answer↓}}}:$

$\huge{\fcolorbox{gold}{Red}{1000}}$

Step-by-step explanation:

$\huge \underline \mathfrak\color{red} {Given,}$

• Dimensions of the floor = 3m × 3.4m
• Dimensions of the tiles = 10cm × 12cm

$\huge \underline \mathfrak\color{red} {To\:Find}$

• Number of tiles required for covering the floor.

$\huge \underline \mathfrak\color{red} {Procedure,}$

$area \: of \: the \: floor = 3m \times 3.4m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 10.2 {m}^{2}$

$area \: of \:t he \: tiles = 10cm \times 12cm \\ \: \: \: \: \: \:\: \: \: \: \: \: \: \:\: \: \: \: = 120 {cm}^{2}$

We jave to convert the units into same unit. Let's convert the m² into cm²

Since,

1 m² = 10000cm²

Therefore,

10.2 m² = 10.2×10000cm²

10.2 m² = 102000cm²

So, the area of the floor is 102000cm²

Now,

$no. \: of \: tiles \: required = \frac{area \: of \: floor}{area \: of \: tiles}$

$= \frac{102000}{102}$

$= 1000$

Therefore, a total of 1000 tiles are required to cover the entire floor