find the area of polygon
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(1)area of the figure = area of trapezium tsrp+areaof triangle pqr =1/2×(6+10)×4 + 1/2×10×5
=32+25
=57cm2
(2). area of figure=ar.of(abf+fbc+fcd+fde)
=1/2×{(2×6.5)(7×4)(7×4)(5×2)}
=1/2×(40040)
=20020cm2
=32+25
=57cm2
(2). area of figure=ar.of(abf+fbc+fcd+fde)
=1/2×{(2×6.5)(7×4)(7×4)(5×2)}
=1/2×(40040)
=20020cm2
Answered by
1
1/2xa+b×h (for trapezium prst)
1/2×16×4
32
now
area of triangle ptq
1/2×base ×height
1/2×10×5
25
now sum of both ptrst
32 +25
57
1/2×16×4
32
now
area of triangle ptq
1/2×base ×height
1/2×10×5
25
now sum of both ptrst
32 +25
57
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