Question

find the area of polygon

Answer 1

hope it's help u.....

Answer 2

$join \: bd \\ {bd}^{2} = {ab}^{2} + {da}^{2} \\ bd \: = \sqrt{1681} = 41 \\ in \: triangle \: dab \\ s = \frac{41 + 9 + 40}{2} = 45 \\ area = \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{45(45 - 41)(45 - 9)(45 - 40)} \\ = \sqrt{45 \times 4 \times 36 \times 5} \\ = \sqrt{5 \times 9 \times 4 \times 9 \times 4 \times 5} \\ = 5 \times 9 \times 4 = 180 {cm}^{2} - - - -(i) \\ \\ in \: triangle \: dcb \\ s = \frac{41 + 15 + 28}{2} = 42 \\ area = \sqrt{42(42 - 41)(42 - 15)(42 - 28)} \\ = \sqrt{42 \times 1 \times 27 \times 14} \\ = \sqrt{7 \times 3 \times 2 \times 3 \times 3 \times 3 \times 7 \times 2} \\ = 7 \times 3 \times 3 \times 2 = 126 {cm}^{2} \\ area \: of \: the \: figure = 180 + 126 = 306 {cm}^{2}$