Question

find the area of quadrant of a circle. whose circumference is 44 cm

Answer 1

Happy to help u...
Hope it's help.

Answer 2

Given,

• $\sf{Circumference\:of\:the\:circle\:is\:44\:cm}$

To find,

• $\sf{Area\:of\:quadrant}$

Solution,

It should be noted that a quadrant of a circle is a sector which is making an angle of 90°

• $\sf{Let\:the\:radios\:of\:the\:circle\:be\:r}$

• As,

$\large{\sf{C=2πr=44}}$

$\large\sf{⇒R=\frac{44}{2π}\:cm}$

$\large\sf{⇒ R=7\:cm}$

• So,

$\bf{Area\:of\:the\:quadrant,}$

$\sf{= \frac{θ}{360°} ×πr^2}$

• Here, θ = 90°

• So,

$\sf\large{A=\frac{90°}{360°}×πr^2\:cm^2}$

$\sf\large{=\frac{1}{4}×π (7)^2\:cm^2}$

$\sf\large{=\frac{1}{4}×π×7×7\:cm^2}$

$\sf\large{=\frac{1}{4}×\frac{22}{7}×7×7\:cm^2}$

$\sf\large{=\frac{77}{2}\:cm^2}$

$\sf\large{=38.5\:\:cm^2}$

____________________________

$\large{ \underline{ \overline{ \mid{ \rm{ \red{Answer→38.5\:\:cm^2}} \mid}}}}$

____________________________