Question

Find the area of quadrilateral ABCD given
in the below figure​

Answer 1

Answer:

the answer is

Step-by-step explanation:

so first we clearly see that diagnaol dived the quadrilateral into two triangle

so first we find the area of triangle onle then triangle second

triangle a area =√s-a × s-b ×s-c

where s = a+b+c/2

s=12+6+6/2s

s= 12

area of triangle =√12-12×12-6×12-6

area of triangle=√6×6

area of triangle=6cm^3

then we find the are of second triangle using same formula

so

s=6+7+15/2

s=14

aee of triangle b=√14-7 × 14-6 × 14-15

=√7×8×-1

we also can w√7×8×-1=√7×2×2×2×-1

=2√7×2×-1

=2√-14 cm^3

so are of quadratic =6cm^3+2√14^ cm^3

=8√14 cm^3

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