Question

Find the area of quadrilateral ABCD in which AB = 50 m, BC = 60 m, CD =30 m, DA = 90 m and BD = 70 m.
(use
$(\sqrt{5} = 2.24 and \sqrt{11} = 3.34)$


​

Answer 1

Answer:

In quadrilateral abcd.

there are two triangles abd & bcd

First area of triangle abd

using herons formula

s=90+50+70/2= 210/2= 105

area of triangle abd=

\sqrt{s{ s - a} {s - b} {s - c}

=525√5

similarly find the area of triangle bcd

put the value of √5&√11

then add both the areas and get your answer .

Step-by-step explanation:

Thank u