Question

find the area of quadrilateral ABCD in which AB=50m,BC=60m,CD=30m,DA=90m and BD=70m​

Answer 1

Answer:

Step-by-step explanation:

in triangle BCD,

semiperimeter (s) = BC + CD + BD/2

s = 60 + 30 + 70 /2

s = 160/2

s = 80

​a = root[80 x (80-60) (80-30) (80 - 70)]

a = root[80 x 20 x 50 x 10]

a = root[ 10 x 4 x 2 x 2 x 10 x 5 x 10 x 10]

a = 10 x 4 x 10 root(5)

a = 400xroot(5)

a = 894.4 (approx)

In triangle ABD,

semiperimeter (s) = AB + BD + DA/2

s = 50 + 70 + 90/2

s = 210/2

s = 105

​a = root[105 x (105- 50) (105-90) (105 - 70)]

a = root[105 x 55 x 15 x 35]

a = root[ 5 x 7 x 3 x 5 x 11 x 5 x 3 x 7 x 5]

a = 25 x 7 x 3 root(11)

a = 525 * root(11)

a = 1741.2 (approx)

Total area = ​894.4 + ​1741.2

= 2635.6 cm2(approx

Answer 2

Answer:

180 is correct answer I think