Question

find the area of quadrilateral ABCD in which diagonal BD = 24 cm AL perpendicular BD and CM perpendicular BD such that AL = 5 cm and CM = 8 cm​

Answer 1

Answer:

area of quadrilateral ABCD=AREA of triangle ABD+area of triangle CBD

=1/2×AL×BD+1/2×CM×BD

=1/2×BD(AL+CM)

=1/2×24(5+8)

=12(13)

=156 sq.cm

Answer 2

Answer:

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