Math, asked by Anonymous, 1 year ago

Find the area of Quadrilateral PQRS where verticles are P ( -5 , -3 ) , Q ( -4 , -6 ) , R ( 2 , -3 ) and S ( 1 , 2 ) .
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Answered by sprao534
1
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Answered by Anonymous
4
Area of triange=1/2
in \: triangle \: pqs \\ area \: of \: triangle = 1 \div 2 | - 5( - 6 - 2)  - 4(2 + 3) + 1( - 3 + 6)|
=1/2|-5(-8)-4(5)+1(3)|

=1/2|40-20+3|

=1/2|23|

=11.5

In qrs

=1/2|-4(-5)+2(8)+1(-3)|

=1/2|20+18-3|

=1/2|35|

=17.5


Area of quadrilateral= area of pqs + area of qrs


= 11.5+17.5


=29
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