Math, asked by v7egeswitafatharma, 1 year ago

Find the area of quadrilateral whose diagonals measures 48m and 32m respectively and bisect each other at right angles.

Answers

Answered by mysticd
39

Answer:

 Area \: of \: the \: quadrilateral= 768\: m^{2}

Step-by-step explanation:

ABCD is a quadrilateral.

AC and BD are two diagonals bisect each other

perpendicularly.

AC = 48 m ,

BD = 32 m

OB = OD = BD/2 = 32/2 = 16 m

 Area \: of \: the \: quadrilateral \\=Area \: of \: \triangle ACD + area \: of \: \triangle ABC\\=\frac{1}{2}\times AC \times OD +\frac{1}{2}\times AC \times OB \\=\frac{1}{2}\times 48 \times 16+\frac{1}{2}\times 48 \times 16= 24 \times 16 + 24\times 16\\= 384 + 384\\=768 \: m^{2}

Therefore,

 Area \: of \: the \: quadrilateral= 768\: m^{2}

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Answered by shishupalkumar1120
0

Answer:

ABCD is quadrilateral with diagonal 48m and 32 m

Step-by-step explanation:

area=768 m²

Attachments:
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