find the area of quadrilateral whose one diagonal is 20 cm long and the perpendicular to this diagonals from other vertices are of length 99 cm and 15 CM
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Area of a triangle = 1/2*b*h
Here Two triangles so
1/2*20(99+15) = 10*114 = 1140 cm^3
Here Two triangles so
1/2*20(99+15) = 10*114 = 1140 cm^3
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