Find the area of quadrilateral whose vertices are (–5, 7), (–4, –5), (–1, –6) and (4, 5)
Answers
72sq units is the right answer
Given : A quadrilateral whose vertices are (–5, 7), (–4, –5), (–1, –6) and (4, 5)
To find : area of quadrilateral
Solution:
quadrilateral vertices are (–5, 7), (–4, –5), (–1, –6) and (4, 5)
Lets break Quadrilateral into two triangles
(–5, 7), (–4, –5)(–1, –6) & (–5, 7), ( 4, 5)(–1, –6)
Area of Triangle
(–5, 7), (–4, –5)(–1, –6)
= (1/2) | -5 ( -5 -(-6)) -4(-6 -7) - 1(7 -(-5))|
= (1/2) | -5(1) - 4(-13) -1(12) |
= (1/2) | -5 + 52 - 12 |
= (1/2) | 35 |
= 35/2
Area of Triangle
(–5, 7), (4, 5)(–1, –6)
= (1/2) | -5 ( 5 -(-6)) +4(-6 -7) - 1(7 - 5))|
= (1/2) | -5(11) + 4(-13) -1( 2) |
= (1/2) | -55 - 52 - 2 |
= (1/2) | -109 |
= 109/2
Area of Quadrilateral = 35/2 + 109/2
= 144/2
= 72
Area of Quadrilateral = 72 sq units
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