Question

Three consecutive integers are such that when they are taken in increasing
multiplied by 2,3 and 4 respectively, they add up to 74. Find these number​

Answer 1

Answer:

Let three integers be x,x+1,x+2

According to Question , 2(x) + 3(x+1) + 4(x+2) = 74

=》》2x + 3x + 3 + 4x + 8 = 74

=》》9x + 11 = 74

=》》9x = 74 -11

=》》9x = 63

=》》 x = 63 / 9 = 7

x = 7 x + 1 = 8 x + 2 = 9

therefore three nos are 7 , 8 , 9

Step-by-step explanation:

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Answer 2

Given :

• Three consecutive integers are taken in increasing multiplied by 2,3 and 4.

• They add up to 74.

To find :

• Those numbers =?

Step-by-step explanation:

Let, the three consecutive integers be x, x + 1 and x + 2.

And, They are taken in increasing multiplied by 2,3 and 4.

So, x → 2(x) = 2x

x + 1 = 3(x + 1)

x + 2 = 4(x + 2)

According to the question,

➟ 2x + 3(x + 1) + 4(x + 2) = 74

➟ 2x + 3x + 3 + 4x + 8 = 74

➟ 2x + 3x + 4x + 3 + 8 = 74

➟ 9x + 11 = 74

➟ 9x = 74 - 11

➟ 9x = 63

➟ x = 63/9

➟ x = 7

Therefore, We know that value of x = 7.

Hence,

x = 7

x + 1 → 7 + 1 = 8

x + 2 → 7 + 2 = 9

Thus, The integers are 7,8 and 9.