find the area of quadrilaterial
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in first triangle =
a= 8cm
b= 5cm
c= 4cm
s= 8+5+4/2 = 17/2 = 8.5 cm
area of triangle = √s(s-a)(s-b)(s-c)
= √ 8.5(8.5-8)(8.5-5)(8.5-4)
= √ 8.5 (.5)(3.5)(4.5)
= √ 85/10× 5/10 × 35/10 × 45/10
=.√ 17/2 × 1/2 × 7/2 × 9/2
a= 8cm
b= 5cm
c= 4cm
s= 8+5+4/2 = 17/2 = 8.5 cm
area of triangle = √s(s-a)(s-b)(s-c)
= √ 8.5(8.5-8)(8.5-5)(8.5-4)
= √ 8.5 (.5)(3.5)(4.5)
= √ 85/10× 5/10 × 35/10 × 45/10
=.√ 17/2 × 1/2 × 7/2 × 9/2
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