Find the area of rectangle whose length is four times its breadth and the breadth is 3a
Answers
Answered by
45
let length =4×3 a =12 a
breadth =3a
area of rectangle = length × breadth
12a×3a
36a
![12a \times 3a = 36a = \:area \: of \: retangle 12a \times 3a = 36a = \:area \: of \: retangle](https://tex.z-dn.net/?f=12a+%5Ctimes+3a+%3D+36a+%3D++%5C%3Aarea+%5C%3A+of+%5C%3A+retangle)
breadth =3a
area of rectangle = length × breadth
12a×3a
36a
Answered by
12
Answer:
Let length =4*3a=12a
breadth=3a
Area= length*breadth
12a*3a
36a
friend , mark it as brilliant please
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