Question

find the area of rectangle whose perimeter is 44cm length is 20 cm
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Answer 1

$perimeter \: of \: rectangle = 44 \: cm \\ length = 20 \: cm \\ \\ \boxed{perimeter \: of \: rectangle = 2(l + b)} \\ 44 \\ = = 2(20 + b) \\ 44 = 40 + b \\ b = 44 - 40 \\ breadth = 4 \: cm \\ \\ \boxed{Area \: of \: rectangle = length \times breadth} \\ 20 \times 4 \\ = 80 \: {cm}^{2}$

Answer 2

❁Required Answer :

we know that ,

${ \to \bf {perimeter \: of \: rectangle = 2(l + b)}}$

Here given,

lenght = 20cm

perimeter = 44cm

to find breath.

= 20cm ×2=40cm

=40-44 /2=4/2=2

$\rm\: thus \: breath = 2cm$

now we need to find area

${ \to\bf{area \: of \: rectangle = l \times b}}$

$= 20 \times 2 = 40$

${\red {\tt{thus \: area \: = 40sqcm}}}$

Recalling Formulas:

$\to \: perimeter \: of \: squares = 4 \times sides$

$\to \: perimeter \: of \: triangle = a + b + c$

$\to \: area \: of \: square \: = side \times side$

$\to \: area \: of \: triangle = \frac{1}{2} \times base \times height$