Find the area of rectangle whose perimeter is 48cm and breadth is 6 mm
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the breadth = 6/10 cm
= 0.6 cm
the perimeter of rectangle = 48 cm
now, perimeter of rectangle = 2×( l+ b)
48 = 2 × ( l + 0.6)
48/2 = l + 0.6cm
24 - 0.6 = l
l = 23.4 cm
hence area of rectangle = l×b
= 23.4 × 0.6cm^2
= 14.04 cm^2
= 0.6 cm
the perimeter of rectangle = 48 cm
now, perimeter of rectangle = 2×( l+ b)
48 = 2 × ( l + 0.6)
48/2 = l + 0.6cm
24 - 0.6 = l
l = 23.4 cm
hence area of rectangle = l×b
= 23.4 × 0.6cm^2
= 14.04 cm^2
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