find the area of rectangle whose sides are (4x+1)cm and (2x-5)
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4x+12 x minus 5 cm 3x+1234
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length = (4x + 1)
breadth = (2x - 5)
area = l×b
= (4x + 1) × (2x - 5)
= 4x(2x - 5) + 1(2x - 5)
= 8x^2 - 20x + 2x - 5
= 8x^2 - 18x - 5
breadth = (2x - 5)
area = l×b
= (4x + 1) × (2x - 5)
= 4x(2x - 5) + 1(2x - 5)
= 8x^2 - 20x + 2x - 5
= 8x^2 - 18x - 5
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