Question

Find the area of rectangles with the following pairs of monomials as their length and breadth respectively: (2a²b, 3ab) proper solution​

Answer 1

Question:

Find the area of rectangles with the following pairs of monomials as their length and breadth respectively: (2a²b, 3ab) proper solution.

To find:

To find the area of rectangle.

Answer:

$\sf \red{\underline{ \: \bold{Area \: of \: rectangle \: is \: 6 {a}^{3} {b}^{2} } \: }}$

Given data:

$Length \: (l) = 2 {a}^{2}b$

$Breadth \: (b) = 3ab$

Step-by-step explanation:

$\boxed{Area \: of \: rectangle = l \times b}$

$\longrightarrow 2 {a}^{2}b \times 3ab$

$\longrightarrow 6 {a}^{3} {b}^{2}$

$\boxed{\therefore Area \: of \: rectangle \: is \: 6 {a}^{3} {b}^{2} }$

Formula used:

$\star Area \: of \: rectangle = l \times b$