find the area of rectangular plot, one side of which is 48m and its diagonal is 50m
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Answered by
2
one side=48m
diagonal=50m
other side=x
by Pythagoras theorem, (since all the angles of a rectangle are 90degree)
(50)^2= (48)^2+ x^2
2500=2304+x^2
2500-2304=x^2
196=x^2
root 196= x
14=x
the other side =14
area=l*b
=14*48
=672m^2
diagonal=50m
other side=x
by Pythagoras theorem, (since all the angles of a rectangle are 90degree)
(50)^2= (48)^2+ x^2
2500=2304+x^2
2500-2304=x^2
196=x^2
root 196= x
14=x
the other side =14
area=l*b
=14*48
=672m^2
Answered by
2
since all the angles of the rectngle are 90 degrees and diagonal divedes it into two right angled triangles.
using pythagoras theoram

p=
p=2500-2304
p=
p=14m
then area of rectangular plot will be 48*14=672
hope it helps
using pythagoras theoram
p=
p=2500-2304
p=
p=14m
then area of rectangular plot will be 48*14=672
hope it helps
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