Find the area of rectangular plot one side of which is 48m and its diagonal is 50m for 7 standard which is design by r.S.Aggarwal
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34
Solutions :-
Given :
One of the side of rectangular plot = b = 48 m
Its Diagonal = d = 50 m
Find the length of other side (a) :-
By Pythagoras theorem,
a² + b² = d²
=> a² + (48)² = (50)²
=> a² + 2304 = 2500
=> a² = 2500 - 2304
=> a = √196 = 14
Now,
Find the area of rectangular plot :-
We know that,
Area of rectangle = (Length × Breadth) sq. units
= (14 × 48) m²
= 672 m²
Hence,
Area of rectangular plot = 672 m²
Given :
One of the side of rectangular plot = b = 48 m
Its Diagonal = d = 50 m
Find the length of other side (a) :-
By Pythagoras theorem,
a² + b² = d²
=> a² + (48)² = (50)²
=> a² + 2304 = 2500
=> a² = 2500 - 2304
=> a = √196 = 14
Now,
Find the area of rectangular plot :-
We know that,
Area of rectangle = (Length × Breadth) sq. units
= (14 × 48) m²
= 672 m²
Hence,
Area of rectangular plot = 672 m²
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Solution:
Given that,
One side of the rectangular plot = 48 m
Diagonal of the rectangular plot = 50 m
Area of the rectangular plot = ?
Now,
Let the breadth be X m.
By Pythagoras Therom,
⇒ Diagonal² = length² + breadth²
⇒ 50² = 48² + x²
⇒ 2500 - 2304 = x²
⇒ x = √196 = 14 m
So, The Breadth is 14 m.
We have,
Area = length × breadth
⇒ 48 m × 14 m
⇒ 676 m²
Hence, The Required Area Of rectangular plot is 676 m².
Given that,
One side of the rectangular plot = 48 m
Diagonal of the rectangular plot = 50 m
Area of the rectangular plot = ?
Now,
Let the breadth be X m.
By Pythagoras Therom,
⇒ Diagonal² = length² + breadth²
⇒ 50² = 48² + x²
⇒ 2500 - 2304 = x²
⇒ x = √196 = 14 m
So, The Breadth is 14 m.
We have,
Area = length × breadth
⇒ 48 m × 14 m
⇒ 676 m²
Hence, The Required Area Of rectangular plot is 676 m².
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