Question

find the area of rectangular whose perimeter 100 metter and breadth 20 metter​

Answer 1

Answer:

Given

perimeter= 100 m

breadth =20m

as perimeter =2(l+b)

100=2(l+20)

100÷2=l+20

50=l+20

l=50-20

l=30m

then

area =l×b

=30m×20m

=600m^2

so your ans is 600 m^2....

Answer 2

• perimeter = 100m
• breadth = 20m
• length = ?

perimeter of rectangle = 2(l + b)

$100 = 2(l + 20)$

$100 = 2l + 40$

$60 = 2l$

$30 = l$

since, the length of rectangle be 30 m...

area of rectangle = l × b

$area = 30 \times </strong><strong>2</strong><strong>0$

$area = </strong><strong>6</strong><strong>00 {m}^{2}$

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hope!!...it helps uhh...❣️