Question

A capacitor of capacitance 1 uF is charged by connecting a battery
of negligible internal resistance and emf 10 V across it. Calculate
the amount of charge supplied by the battery in charging the
capacitor fully.
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Answer 1

Explanation:

I hope this will help you

Answer 2

The charge in the capacitor is $10^{-5}\ C$.

Given :

Capacitance of capacitor , $C=1\ \mu F=10^{-6} \ F\ .$

Emf of cell is given as , 10 V and there is no internal resistance .

Therefore , Potential difference across the cell is also equal to emf i.e V = 10 V

We need , to find the charge on the capacitor ,

We know , $Q=CV$

Putting value of C and V in above equation we get ,

$Q=10^{-6}\times 10\ C\\\\Q=10^{-5}\ C$

Therefore , the charge in the capacitor is $10^{-5}\ C$.

Hence , this is the required solution .

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Capacitance

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