find the area of regular hexagon whose one side 4 unit
Answers
Answered by
124
A regular hexagon is composed of six equilateral triangle.
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 6 × √3/4 × 4²
=> 6 × √3/4 × 16
=> 6 × √3 × 4
=> 24√3 square unit
In decimals = 41.57 sq. unit (approx)
Hope it helps dear friend ☺️
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 6 × √3/4 × 4²
=> 6 × √3/4 × 16
=> 6 × √3 × 4
=> 24√3 square unit
In decimals = 41.57 sq. unit (approx)
Hope it helps dear friend ☺️
Answered by
37
Answer:
Step-by-step explanation:
A regular hexagon is composed of six equilateral triangle.
Area of equilateral triangle = √3/4a²
Hence, area of six equilateral triangle = 6√3/4a² which is equal to area of regular hexagon.
Hence area of given regular hexagon
= 6 × √3/4 × 4²
=> 6 × √3/4 × 16
=> 6 × √3 × 4
=> 24√3 square unit
Similar questions