Find the area of rhombus having each equal side as 5 cm and one of its diagonals is 8 cm
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Step-by-step explanation:
lengh of each side of rhombus =5cm
one diagonal =8cm
area of rhombus =1/2×d1× d2
A/Q
1/2×8×6cm2
24cm2
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by pythagoras theoram , ^=square
(AD)^=(AGO)^+(DO)^
5^=4^+X^.........( let consider DO be x)
25=16+X^
25-16=X^
X=3
the length of other diagonal =DO+OB...(OB=DO=3)
=3+3
=6
therefore, the length of one diagonal is 8 cm and other diagonal is 6 cm
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