Question

find the area of Rhombus having side 13 cm and one of its diagonal 10 cm

Answer 1

acc to Pythagoras theorem,
side a² + side b²= hypotenuse ²
now, for finding other diagonal,
13²+13²= hypotenuse ²( other diagonal)
169+169=hypo²
338=hypo²
hyo= √338
so, area of Rhombus is 1/2 d1d2
area= 1/2 10x √338
area= 5x √338
find root 338 by long division and here's ur ans...!
hope it helps