Find the area of rhombus if it's vertices are(3,0)(4,5)(-1,4)&(-2,1)
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in triangle ABC
A(-2,1)= (x1, y1)
B(4,5)= (x2, y2)
C(-1,4)= (x3, y3)
area of triangle=1/2 | x1(y2-y3) + x2(y3-y1) +
x3(y1-y2) |
=1/2 | (-2)(5-4) + (4)(4-1) + (-1)(1-5) |
=1/2 | -2 + 12 + 4 |
=1/2 |14|
= 7
similarly find area of triangle ADC
area of triangle ADC is 0
area of rombus = area of ABC + area of ADC
= 7+0
=7
A(-2,1)= (x1, y1)
B(4,5)= (x2, y2)
C(-1,4)= (x3, y3)
area of triangle=1/2 | x1(y2-y3) + x2(y3-y1) +
x3(y1-y2) |
=1/2 | (-2)(5-4) + (4)(4-1) + (-1)(1-5) |
=1/2 | -2 + 12 + 4 |
=1/2 |14|
= 7
similarly find area of triangle ADC
area of triangle ADC is 0
area of rombus = area of ABC + area of ADC
= 7+0
=7
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Answered by
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HOPE IT IS HELPFUL :)
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please mark brainliest :)
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