find the area of Rhombus of side 17 cm and one of its diagonal is 16 cm long
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by pythagoras theorem
squareroot of (17^2-8^2)=15cm
area of rhombus =(d1×d2 )÷2
(16cm x 30cm)÷2
240cm^2
squareroot of (17^2-8^2)=15cm
area of rhombus =(d1×d2 )÷2
(16cm x 30cm)÷2
240cm^2
Answered by
0
Answer:
240 cm²
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