find the area of rhombus one side of which measures 20cm and one of whose diagonal is 24cm
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Area of rhombus is 384cm2
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area of rhombus= product of diagonals/2
here,
by pythagoras theorem ,
20^2 = 12^2 + (half of second diagoal)^2
400 -144 = half of second diagonal^2
256= half of second diagonal
16 = half of second diagonal
then the second diagonal is of 32cm
then area of rhombus = (32*24)/2
area of rhombus = 16*24
area of rhombus = 384cm^2
here,
by pythagoras theorem ,
20^2 = 12^2 + (half of second diagoal)^2
400 -144 = half of second diagonal^2
256= half of second diagonal
16 = half of second diagonal
then the second diagonal is of 32cm
then area of rhombus = (32*24)/2
area of rhombus = 16*24
area of rhombus = 384cm^2
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