Question

find the area of Rhombus whose each side is 13 M and one of the diagonals is 10m​

Answer 1

Hey there!

Answer:

120 m²

Step-by-step explanation:

♣ Given Data:

Side of rhombus = 13 m

Diagonal of rhombus = 10 m

AC = 10 m

AE = 1/2 * AC = 1/2 * 10 = 5 m

♣ Apply Pythagoras theorem:

In ΔABE,

BE = √AB² - AE²

    = √(13)² - 5²

    = √169 - 25

    = √144

    = 12 m

Now,

BD = 2 * BE = 2 * 12 = 24 m

♣ Finding area using standard formula:

Area = 1/2 * diagonal 1 * diagonal 2

        =1/2 * AC * BD

        = 1/2 * 10 * 24

        = 120 m²

Hope It Helps YoU!

Answer 2

Answer:

ans-120m²

Step-by-step explanation:

PT²+QT²=PQ²

PT²+5²=13²

PT²+25=169

PT²=169-25=144

PT=12

PR=2×PT

=2×12=24

Area of rhombus PQRS=1/2×d1×d2

=1/2×24×10=12m²