Question

Find the area of Rhombus whose one side is 13 cm and one diagonal is 26 cm.

Answer 1

A=pq/2

a=√p^2+q^2/2

Solving forA

A=1/2p√4a^2﹣p^2

= 1/2*24*√4*13^2﹣24^2  

=120cm²

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Answer 2

hi

there is some mistake in your question.

The length if diagonal need to be 24cm.

here is your answer

Area of rhombus = 1/2× product of diagonals.

now, As diagonal of rhombus bisect each other.

Hence,by Pythagoras theorem,

12^2+ oc^2= 13^2

= 144+ OC^2 = 169

=OC= 5 cm

and AC = 5×2=10cm

Now area = 1/2× 10 × 24

= 120cm^2

hope it helps

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