Question

find the area of rhombus whose one side is 17 cm and one diagonal is 30 cm​

Answer 1

Answer:

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Answer 2

$\huge \fbox \green{Solution:}$

Given,

$Side \: Of \: Rhombus = 17cm$

$Diagonal \: Side = 30cm$

$: AB² = AE² + BE²$

$⇒(17 {)}^{2} = (15 {)}^{2} + B {E}^{2}$

$⇒B {E}^{2} = 289 - 225 = 64$

$⇒BE = x = 8$

$: \: BC = 16$

$\sf \colorbox{god} {Area of the Rhombus}$

$= \frac{1}{2} (BC \times A D)$

$= \frac{1}{2} \times 16 \times 30$

$240 {cm}^{2}$

$\\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$