Question

Find the area of rhombus whose perimeter is 100 m and one of whose diagonal is 30 m​

Answer 1

Answer:

p=100

4×s=100

s=100÷4

s=25

now side is 25

as diagonals of rhombus bisects each other at right angle

so half diagonal =30÷2

=15

now applying phythagorous theorem

(h)2=(p)2+(b)2

h=25 p=15 b=?

625=225+b2

625-225=b2

400=b2

b=20

so half diagonal is 20

full diagonal =2×20

=40

area of diagonal =1/2×d1×2

=1/2×30×40

600m2

Answer 2

Answer:

20

Step-by-step explanation:

area of rhombus is D1D2/2

perimeter=4s

100=4S

• S=25
• diagonal of one side 30
• apply Pythagoras theorem
• 25
• ${15 }^{2} + {x}^{2} = {25}^{2}$
• ${x }^{2} = {25}^{2} - {15}^{2}$
• ${x }^{2} = 625 - 225$
• ${x }^{2} = 400$
• $x = 20$